#15  
11-04-2010, 08:09 PM
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Agatha Agatha
 
: Sep 2010
: :*`*:.
: 560
: 0.21
: 0
3 3
Agatha is on a distinguished road

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:




῿
24



㿿!
4/3*^2
4/3*16
=43





[1 /(1/3) ][1/(1/2) ][(1/3)(1/2)]=4


81 + (3) - ( (3) + 3 )=
81+3-3-3( )

81-3
=78







(-3)^2 = 25

4
35 67 96
:

35







:-3de1c49c1c:

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